x^2+484=625

Solution for x^2+484=625 equation:

x^2+484=625

We move all terms to the left:

x^2+484-(625)=0

We add all the numbers together, and all the variables

x^2-141=0

a = 1; b = 0; c = -141;
Δ = b2-4ac
Δ = 02-4·1·(-141)
Δ = 564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{564}=\sqrt{4*141}=\sqrt{4}*\sqrt{141}=2\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{141}}{2*1}=\frac{0-2\sqrt{141}}{2}
=-\frac{2\sqrt{141}}{2}
=-\sqrt{141}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{141}}{2*1}=\frac{0+2\sqrt{141}}{2}
=\frac{2\sqrt{141}}{2}
=\sqrt{141}
$